What is the domain of f(x)=(ln(x^2-9))/(-x^2+x-12) ?

The domain of f(x)=(ln(x^2-9))/(-x^2+x-12) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(ln(x^2-9))/(-x^2+x-12)

domain

f (x) = \frac{ln ( x ^{2} - 9 )}{- x ^{2} + x - 12}

x < - 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (3, \infty)

Solution steps

Find positive values for logs:

x < - 3 or x > 3

The function domain

x < - 3 or x > 3

f (x) = lo g_{10} (x - 4)

\frac{( 4 a ^{2} - 20 a + 25 )}{25 - 4 a ^{2}}

\frac{1}{2} x - 3

f (x) = - x + 2

f (x) = \frac{3 x + 2}{1 - x}

What is the domain of f(x)=(ln(x^2-9))/(-x^2+x-12) ?
The domain of f(x)=(ln(x^2-9))/(-x^2+x-12) is x<-3\lor x>3