What is the domain of f(x)= 1/(x^2+25) ?

The domain of f(x)= 1/(x^2+25) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(x^2+25)

domain

f (x) = \frac{1}{x ^{2} + 25}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

4 + x - 2

\frac{1}{( x - 1 ) ^{2}}

f (x) = \frac{2}{( x ^{2} - 4 )}

f (x) = - x^{4} + 2 x^{2}

f (x) = \frac{ln ( x )}{x}

What is the domain of f(x)= 1/(x^2+25) ?
The domain of f(x)= 1/(x^2+25) is -infinity <x<infinity