What is the domain of f(x)=(x^2+2x-3)/(2x^2-4x) ?

The domain of f(x)=(x^2+2x-3)/(2x^2-4x) is x 2

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domain of f(x)=(x^2+2x-3)/(2x^2-4x)

domain

f (x) = \frac{x ^{2} + 2 x - 3}{2 x ^{2} - 4 x}

x < 0 or 0 < x < 2 or x > 2

Solution steps

Find undefined (singularity) points:

x = 2, x = 0

The function domain

x < 0 or 0 < x < 2 or x > 2

f (x) = \frac{1}{1 - x}

f (x) = \frac{x + 1}{x ^{2}}

f (x) = ∣ x - 1 ∣ + 2

cos (2 x)

f (x) = x^{2} - 4 x - 5

What is the domain of f(x)=(x^2+2x-3)/(2x^2-4x) ?
The domain of f(x)=(x^2+2x-3)/(2x^2-4x) is x<0\lor 0<x<2\lor x>2