What is the domain of f(x)= 1/(sqrt(1.5x-6.2x^2)) ?

The domain of f(x)= 1/(sqrt(1.5x-6.2x^2)) is 0<x< 15/62

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domain of f(x)= 1/(sqrt(1.5x-6.2x^2))

domain

f (x) = \frac{1}{1.5 x - 6.2 x ^{2}}

0 < x < \frac{15}{62}

Solution steps

Find non-negative values for radicals:

0 \leq x \leq \frac{15}{62}

Find undefined (singularity) points:

x = 0, x = \frac{15}{62}

Combine real regions and undefined points for final function domain

0 < x < \frac{15}{62}

f (x) = ln (3 x - 6)

(x - 5)^{2}

f (x) = \frac{x ^{2} - 2 x + 1}{( x + 2 ) ( x + 1 )}

4 - x^{4}

\frac{2 x ^{2}}{x ^{2} - 9}

What is the domain of f(x)= 1/(sqrt(1.5x-6.2x^2)) ?
The domain of f(x)= 1/(sqrt(1.5x-6.2x^2)) is 0<x< 15/62