What is the inverse of f(x)=log_{10}(x+1)-3 ?

The inverse of f(x)=log_{10}(x+1)-3 is 10^{x+3}-1

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inverse of f(x)=log_{10}(x+1)-3

inverse

f (x) = lo g_{10} (x + 1) - 3

1 0^{x + 3} - 1

Solution steps

y = lo g_{10} (x + 1) - 3

Replace

x

with

y

x = lo g_{10} (y + 1) - 3

Solve for

y, x = lo g_{10} (y + 1) - 3

1 0^{x + 3} - 1

f (x) = \frac{x - 3}{8}

f (x) = \frac{3 x - 2}{x - 1}

f (x) = lo g_{10} (3 x)

f (x) = \frac{( 2 x + 3 )}{( x + 2 )}

f (x) = 6 x + 24

What is the inverse of f(x)=log_{10}(x+1)-3 ?
The inverse of f(x)=log_{10}(x+1)-3 is 10^{x+3}-1