What is the inverse of f(x)= 1/(x^3)+4 ?

The inverse of f(x)= 1/(x^3)+4 is cube root of 1/(x-4)

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inverse of f(x)= 1/(x^3)+4

inverse

f (x) = \frac{1}{x ^{3}} + 4

3 \frac{1}{x - 4}

Solution steps

y = \frac{1}{x ^{3}} + 4

Replace

x

with

y

x = \frac{1}{y ^{3}} + 4

Solve for

y, x = \frac{1}{y ^{3}} + 4

3 \frac{1}{x - 4}

- 2 x + 6

f (x) = \frac{4 - x}{7 - 2 x}

f (x) = (8 - 2 x)^{2}

2^{x + 1}

y = 8 x^{2} + 6

What is the inverse of f(x)= 1/(x^3)+4 ?
The inverse of f(x)= 1/(x^3)+4 is cube root of 1/(x-4)