What is the inverse of f(x)=((2x-5))/(x-7) ?

The inverse of f(x)=((2x-5))/(x-7) is (-5+7x)/(x-2)

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inverse of f(x)=((2x-5))/(x-7)

inverse

f (x) = \frac{( 2 x - 5 )}{x - 7}

\frac{- 5 + 7 x}{x - 2}

Solution steps

y = \frac{2 x - 5}{x - 7}

Replace

x

with

y

x = \frac{2 y - 5}{y - 7}

Solve for

y, x = \frac{2 y - 5}{y - 7}

\frac{- 5 + 7 x}{x - 2}

f (x) = 8 x^{5} - 7

g (x) = \frac{x + 3}{2 x - 1}

- 3 x

f (x) = 9 x + x + 82

f (x) = 3 (x + 2)^{2} - 5, x \leq - 2

What is the inverse of f(x)=((2x-5))/(x-7) ?
The inverse of f(x)=((2x-5))/(x-7) is (-5+7x)/(x-2)