What is the E(x)=(3(x-1)^2+(3x+1)^2)/(1+3x^2) ?

The E(x)=(3(x-1)^2+(3x+1)^2)/(1+3x^2) is

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E(x)=(3(x-1)^2+(3x+1)^2)/(1+3x^2)

E (x) = \frac{3 ( x - 1 ) ^{2} + ( 3 x + 1 ) ^{2}}{1 + 3 x ^{2}}

Domain : - \infty < x < \infty

Range : f (x) = 4

Y Intercepts : (0, 4)

Asymptotes : Horizontal y = 4

Extreme Points : None

Solution steps

Domain of

\frac{3 ( x - 1 ) ^{2} + ( 3 x + 1 ) ^{2}}{1 + 3 x ^{2}} : - \infty < x < \infty

Range of

\frac{3 ( x - 1 ) ^{2} + ( 3 x + 1 ) ^{2}}{1 + 3 x ^{2}} : f (x) = 4

Axis interception points of

\frac{3 ( x - 1 ) ^{2} + ( 3 x + 1 ) ^{2}}{1 + 3 x ^{2}} :

Y Intercepts

: (0, 4)

Asymptotes of

\frac{3 ( x - 1 ) ^{2} + ( 3 x + 1 ) ^{2}}{1 + 3 x ^{2}} :

Horizontal

: y = 4

Extreme Points of

\frac{3 ( x - 1 ) ^{2} + ( 3 x + 1 ) ^{2}}{1 + 3 x ^{2}} :

None

f (x) = \frac{x + 5}{x + 3}

f (x) = arctan (e^{3 x})

f (p) = p^{2} + 6 p - 1

f (x) = - 2 x (x + 1) (x + 2)

f (x) = 6 x ln (x)

What is the E(x)=(3(x-1)^2+(3x+1)^2)/(1+3x^2) ?
The E(x)=(3(x-1)^2+(3x+1)^2)/(1+3x^2) is