What is the f(x)= 10/3 x^3-15x^2+20x,0<= x<= 4 ?

The f(x)= 10/3 x^3-15x^2+20x,0<= x<= 4 is

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f(x)= 10/3 x^3-15x^2+20x,0<= x<= 4

f (x) = \frac{10}{3} x^{3} - 15 x^{2} + 20 x, 0 \leq x \leq 4

Domain : 0 \leq x \leq 4

Range : 0 \leq f (x) \leq \frac{160}{3}

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Minimum (0, 0), Maximum (1, \frac{25}{3}), Minimum (2, \frac{20}{3}), Maximum (4, \frac{160}{3})

Solution steps

Domain of

\frac{10}{3} x^{3} - 15 x^{2} + 20 x, 0 \leq x \leq 4 : 0 \leq x \leq 4

Range of

\frac{10}{3} x^{3} - 15 x^{2} + 20 x, 0 \leq x \leq 4 : 0 \leq f (x) \leq \frac{160}{3}

Axis interception points of

\frac{10}{3} x^{3} - 15 x^{2} + 20 x, 0 \leq x \leq 4 :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{10}{3} x^{3} - 15 x^{2} + 20 x, 0 \leq x \leq 4 :

None

Extreme Points of

\frac{10}{3} x^{3} - 15 x^{2} + 20 x, 0 \leq x \leq 4 :

Minimum

(0, 0),

Maximum

(1, \frac{25}{3}),

Minimum

(2, \frac{20}{3}),

Maximum

(4, \frac{160}{3})

f (x) = \frac{4 - x}{16 x - x ^{2}}

p (x) = 4

f (x) = \frac{π}{2} + arcsec (\frac{1}{x ^{2}})

y = 2 x^{2} + 7 x + 3

p (x) = x

What is the f(x)= 10/3 x^3-15x^2+20x,0<= x<= 4 ?
The f(x)= 10/3 x^3-15x^2+20x,0<= x<= 4 is