invers sec(x)

Lösung

invers

sec (x)

arcsec (x)

Schritte zur Lösung

sec (a) = b \Rightarrow a = arcsec (b)

arcsec (y)

Ersetze

y = x

arcsec (x)

d o main f (x) = x e^{x}

a sy m pt o t es f (x) = \frac{- 2 x ^{2}}{x ^{2} + 4 x - 5}

in t erce pt s \frac{x ^{2} + 4 x + 4}{x ^{3} + 5 x ^{2}}

cr i t i c a l f (x) = (11 - 5 x) e^{x}

a sy m pt o t es f (x) = \frac{( x ^{3} - 9 x )}{x + 2}