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Popular >

p(t)=(80(1+0.3t))/(2+0.02t)

Solution

p (t) = \frac{80 ( 1 + 0.3 t )}{2 + 0.02 t}

Solution

Domain : t < - 100 or t > - 100

Range : f (t) < 1200 or f (t) > 1200

X Intercepts : (- 3.33333 \dots, 0), Y Intercepts : (0, 40)

Asymptotes : Vertical t = - 100, Horizontal y = 1200

Extreme Points : None

+1

Solution steps

Domain of

\frac{80 ( 1 + 0.3 t )}{2 + 0.02 t} : t < - 100 or t > - 100

Range of

\frac{80 ( 1 + 0.3 t )}{2 + 0.02 t} : f (t) < 1200 or f (t) > 1200

Axis interception points of

\frac{80 ( 1 + 0.3 t )}{2 + 0.02 t} :

X Intercepts

: (- 3.33333 \dots, 0),

Y Intercepts

: (0, 40)

Asymptotes of

\frac{80 ( 1 + 0.3 t )}{2 + 0.02 t} :

Vertical

: t = - 100,

Horizontal

: y = 1200

Extreme Points of

\frac{80 ( 1 + 0.3 t )}{2 + 0.02 t} :

None

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Frequently Asked Questions (FAQ)

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