What is the f(x)=(x^3+2)/(2x^5-5x^4+7x^3+4x^2-10+11) ?

The f(x)=(x^3+2)/(2x^5-5x^4+7x^3+4x^2-10+11) is

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f(x)=(x^3+2)/(2x^5-5x^4+7x^3+4x^2-10+11)

f (x) = \frac{x ^{3} + 2}{2 x ^{5} - 5 x ^{4} + 7 x ^{3} + 4 x ^{2} - 10 + 11}

Domain : x < - 0.61427 \dots or x > - 0.61427 \dots

Range : - 4.70285 E 13 < f (x) \leq 2

Asymptotes : Vertical x = - 0.61427 \dots, Horizontal y = 0

Extreme Points : Maximum (- 1.90045 \dots, 0.03299 \dots), Minimum (- 0.30420 \dots, 1.75263 \dots), Maximum (0, 2)

Solution steps

Domain of

\frac{x ^{3} + 2}{2 x ^{5} - 5 x ^{4} + 7 x ^{3} + 4 x ^{2} - 10 + 11} : x < - 0.61427 \dots or x > - 0.61427 \dots

Range of

\frac{x ^{3} + 2}{2 x ^{5} - 5 x ^{4} + 7 x ^{3} + 4 x ^{2} - 10 + 11} : - 4.70285 E 13 < f (x) \leq 2

Axis interception points of

\frac{x ^{3} + 2}{2 x ^{5} - 5 x ^{4} + 7 x ^{3} + 4 x ^{2} - 10 + 11} :

X Intercepts

Y Intercepts

: (0, 2)

Asymptotes of

\frac{x ^{3} + 2}{2 x ^{5} - 5 x ^{4} + 7 x ^{3} + 4 x ^{2} - 10 + 11} :

Vertical

: x = - 0.61427 \dots,

Horizontal

: y = 0

Extreme Points of

\frac{x ^{3} + 2}{2 x ^{5} - 5 x ^{4} + 7 x ^{3} + 4 x ^{2} - 10 + 11} :

Maximum

(- 1.90045 \dots, 0.03299 \dots),

Minimum

(- 0.30420 \dots, 1.75263 \dots),

Maximum

(0, 2)

y = A sin (x)

f (x) = - 6 (3 - 5 x)

f (x) = 4 x^{3} + 5 - 2 x + x^{2}

f (x) = - 7 cos (\frac{1}{2} x + \frac{π}{6}) + 5

What is the f(x)=(x^3+2)/(2x^5-5x^4+7x^3+4x^2-10+11) ?
The f(x)=(x^3+2)/(2x^5-5x^4+7x^3+4x^2-10+11) is