What is the f(x)=tan(x^2)+1 ?

The f(x)=tan(x^2)+1 is Parity: Even Inverse: sqrt(arctan(x-1)),-sqrt(arctan(x-1))

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f(x)=tan(x^2)+1

f (x) = tan (x^{2}) + 1

Parity : Even

Inverse : arctan (x - 1), - arctan (x - 1)

Solution steps

Parity of

tan (x^{2}) + 1 :

Even

Inverse of

tan (x^{2}) + 1 : arctan (x - 1), - arctan (x - 1)

f (x) = - 0.1 x^{4} - 0.15 x^{3} - 0.5 x^{2} - 0.25 x + 1.2

y = x^{2} + 11 x + 24

y = x^{3} - 12 x^{2} + 36 x + 5

f (x) = 2 x ln (x) - 4 x

What is the f(x)=tan(x^2)+1 ?
The f(x)=tan(x^2)+1 is Parity: Even<br/>Inverse: sqrt(arctan(x-1)),-sqrt(arctan(x-1))