inflection f(x)=(4x^2)/(x^2-9)

解答

拐点

f (x) = \frac{4 x ^{2}}{x ^{2} - 9}

无

求解步骤

f^{''} (x) = \frac{216 ( x ^{2} + 3 )}{( x ^{2} - 9 ) ^{3}}

Find intervals:

无

无

in v erse f (x) = cos (x + 1)

e x t re m e f (x) = x^{3} - 3 x + 1

d o main \frac{x}{x ^{2} - 1}

a sy m pt o t es f (x) = \frac{x ^{2} - 1}{4 x - 4}

e x t re m e f (x) = \frac{1}{4} x^{2} + 2 x + 6