What is the asymptotes of f(x)=(4x^2+1)/(2x^2+5x-3) ?

The asymptotes of f(x)=(4x^2+1)/(2x^2+5x-3) is Vertical: x=-3,x= 1/2 ,Horizontal: y=2

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asymptotes of f(x)=(4x^2+1)/(2x^2+5x-3)

asymptotes

f (x) = \frac{4 x ^{2} + 1}{2 x ^{2} + 5 x - 3}

Vertical : x = - 3, x = \frac{1}{2}, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} + 1}{2 x ^{2} + 5 x - 3} : x = - 3, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{4 x ^{2} + 1}{2 x ^{2} + 5 x - 3} : y = 2

Slant Asymptotes of

\frac{4 x ^{2} + 1}{2 x ^{2} + 5 x - 3} :

None

Vertical : x = - 3, x = \frac{1}{2}, Horizontal : y = 2

f (x) = \frac{1}{3} x^{3} - x^{2} - 3 x

f (x) = 3 - 5 x + 10

4 x - 4 y = 36

f (x) = t^{2}

tan (3 x)

What is the asymptotes of f(x)=(4x^2+1)/(2x^2+5x-3) ?
The asymptotes of f(x)=(4x^2+1)/(2x^2+5x-3) is Vertical: x=-3,x= 1/2 ,Horizontal: y=2