What is the domain of f(x)= 5/(2x^{3/2)} ?

The domain of f(x)= 5/(2x^{3/2)} is x>0

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domain of f(x)= 5/(2x^{3/2)}

domain

f (x) = \frac{5}{2 x ^{\frac{3}{2}}}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

f (x) = - 3 x - 2

f (x) = 5 x - 7

f (x) = x^{2} + 2 x + 1

f (x) = 1 + \frac{1}{2 x}

\frac{- 2 x + 6}{x ^{2} - 9}

What is the domain of f(x)= 5/(2x^{3/2)} ?
The domain of f(x)= 5/(2x^{3/2)} is x>0