What is the inverse of f(x)=(x^2+1)/4 ?

The inverse of f(x)=(x^2+1)/4 is sqrt(4x-1),-sqrt(4x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=(x^2+1)/4

inverse

f (x) = \frac{x ^{2} + 1}{4}

4 x - 1, - 4 x - 1

Solution steps

y = \frac{x ^{2} + 1}{4}

Replace

x

with

y

x = \frac{y ^{2} + 1}{4}

Solve for

y, x = \frac{y ^{2} + 1}{4}

4 x - 1, - 4 x - 1

r an g e - x - 3

in v erse \frac{4 s + 12}{s ^{2} + 8 s + 16}

d o main y = ln ∣ x ∣

s im pl i f y (0.2) (3)

s im pl i f y (5.5) (7.1)

What is the inverse of f(x)=(x^2+1)/4 ?
The inverse of f(x)=(x^2+1)/4 is sqrt(4x-1),-sqrt(4x-1)