What is the inverse of f(x)=((x+2))/((x-3)) ?

The inverse of f(x)=((x+2))/((x-3)) is (2+3x)/(x-1)

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inverse of f(x)=((x+2))/((x-3))

inverse

f (x) = \frac{( x + 2 )}{( x - 3 )}

\frac{2 + 3 x}{x - 1}

Solution steps

y = \frac{x + 2}{x - 3}

Replace

x

with

y

x = \frac{y + 2}{y - 3}

Solve for

y, x = \frac{y + 2}{y - 3}

\frac{2 + 3 x}{x - 1}

a sy m pt o t es \frac{7}{3 + e ^{x}}

m o n o t o n e \frac{6 x}{7} \frac{4 x}{3}

r an g e \frac{x ^{2} + 1}{2}

d o main \frac{x ^{2} + 7 x}{5 x ^{2} - 1}

in t erce pt s f (x) = - \frac{1}{2} x^{2} + 4 x - 2

What is the inverse of f(x)=((x+2))/((x-3)) ?
The inverse of f(x)=((x+2))/((x-3)) is (2+3x)/(x-1)