What is the critical f(x)= 3/(9-x^2) ?

The critical f(x)= 3/(9-x^2) is x=0

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critical f(x)= 3/(9-x^2)

critical points

f (x) = \frac{3}{9 - x ^{2}}

x = 0

Solution steps

\frac{3}{9 - x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{3}{9 - x ^{2}} : x < - 3 or - 3 < x < 3 or x > 3

\frac{3}{9 - x ^{2}}

is not defined at

x = - 3, x = 3

, therefore:

x = 0

f (x) = x^{4} - 50 x^{2} + 8

y = x^{2} + 2 x - 8

f (x) = \frac{2}{x + 3}

f (x) = \frac{5 x + 4}{7}

(2.2) (- 3.7)