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Popular >

midpoint (0,-8),(-7,-4)

Solution

midpoint

(0, - 8), (- 7, - 4)

Solution

(- \frac{7}{2}, - 6)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (0, - 8), (x_{2}, y_{2}) = (- 7, - 4)

= (\frac{- 7 + 0}{2}, \frac{- 4 - 8}{2})

Refine

= (- \frac{7}{2}, - 6)

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f (x) = \frac{( x + 1 )}{( x ^{2} + 1 )}

range of x^2-x+3 range

x^{2} - x + 3

critical (x^4)/4-x^2+1 critical points

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Frequently Asked Questions (FAQ)

What is the midpoint (0,-8),(-7,-4) ?
The midpoint (0,-8),(-7,-4) is (-7/2 ,-6)