What is the inverse of f(x)=2x^2+16x+5 ?

The inverse of f(x)=2x^2+16x+5 is (-16+sqrt(8x+216))/4 ,(-16-sqrt(8x+216))/4

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inverse of f(x)=2x^2+16x+5

inverse

f (x) = 2 x^{2} + 16 x + 5

\frac{- 16 + 8 x + 216}{4}, \frac{- 16 - 8 x + 216}{4}

Solution steps

y = 2 x^{2} + 16 x + 5

Replace

x

with

y

x = 2 y^{2} + 16 y + 5

Solve for

y, x = 2 y^{2} + 16 y + 5

\frac{- 16 + 8 x + 216}{4}, \frac{- 16 - 8 x + 216}{4}

f (x) = \frac{( x ^{7} )}{3} + 3

f (x) = - x^{4} - 2 x^{3} + 10 x^{2} + 4 x - 16

5 csc (10 x)

f (x) = - x^{2} + 4 x - 1

x^{3} - 6 x^{2} - 36 x

What is the inverse of f(x)=2x^2+16x+5 ?
The inverse of f(x)=2x^2+16x+5 is (-16+sqrt(8x+216))/4 ,(-16-sqrt(8x+216))/4