What is the critical f(x)=x^2-8x-240 ?

The critical f(x)=x^2-8x-240 is x=4

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critical f(x)=x^2-8x-240

critical points

f (x) = x^{2} - 8 x - 240

x = 4

Solution steps

x^{2} - 8 x - 240

Find where

f^{'} (x)

is equal to zero or undefined

x = 4

Identify critical points not in

f (x)

domain

Domain of

x^{2} - 8 x - 240 : - \infty < x < \infty

All critical points are in domain

x = 4

f (x) = - x - 2

f (x) = \frac{5 x ^{2} + 3}{x + 2}

\frac{x - 8}{x + 4}

f (x) = x^{4} + y^{2} - x y = 16

y = - \frac{1}{6} x + 3, (- 3, 23)