What is the domain of f(x)= 1/(sqrt(x-9)) ?

The domain of f(x)= 1/(sqrt(x-9)) is x>9

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domain of f(x)= 1/(sqrt(x-9))

domain

f (x) = \frac{1}{x - 9}

x > 9

Solution steps

Find non-negative values for radicals:

x \geq 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

x > 9

- 6 cos (5 x)

6 x^{2} + 8 x - 1

f (x) = \frac{10 x - 1}{3 - 5 x}

f (x) = y^{2} - 2

f (x) = 4 x (x + 3) (x - 4)

What is the domain of f(x)= 1/(sqrt(x-9)) ?
The domain of f(x)= 1/(sqrt(x-9)) is x>9