What is the parity (x^2+2x-4)/(5x^4-2x^3-7x^2-39) ?

The parity (x^2+2x-4)/(5x^4-2x^3-7x^2-39) is Neither even nor odd

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

parity (x^2+2x-4)/(5x^4-2x^3-7x^2-39)

parity

\frac{x ^{2} + 2 x - 4}{5 x ^{4} - 2 x ^{3} - 7 x ^{2} - 39}

Neither even nor odd

Solution steps

f (- x) : \frac{x ^{2} - 2 x - 4}{5 x ^{4} + 2 x ^{3} - 7 x ^{2} - 39}

- f (x) : - \frac{x ^{2} + 2 x - 4}{5 x ^{4} - 2 x ^{3} - 7 x ^{2} - 39}

Check parity of

\frac{x ^{2} + 2 x - 4}{5 x ^{4} - 2 x ^{3} - 7 x ^{2} - 39}

Check if Even:

False

Check if Odd:

False

Neither even nor odd

f (x) = x^{3} - 4

cos^{2} (x)

\frac{x ^{2} - 1}{x ^{3}}

f (x) = - 3 + 6 x - x^{3}

f (x) = 5 x + 5

What is the parity (x^2+2x-4)/(5x^4-2x^3-7x^2-39) ?
The parity (x^2+2x-4)/(5x^4-2x^3-7x^2-39) is Neither even nor odd