What is the domain of f(x)=(sqrt(x+3))/(x-9) ?

The domain of f(x)=(sqrt(x+3))/(x-9) is -3 9

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domain of f(x)=(sqrt(x+3))/(x-9)

domain

f (x) = \frac{x + 3}{x - 9}

- 3 \leq x < 9 or x > 9

Interval Notation

[- 3, 9) \cup (9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

- 3 \leq x < 9 or x > 9

y = 4 x - 3

d o main f (x) = 8 + 5 ln (2 x + 3)

in v erse f (x) = \frac{5 x - 9}{9 x + 5}

e x t re m e f (x) = - \frac{40 x}{x ^{2} + 25}

cr i t i c a l x + \frac{4}{x}

What is the domain of f(x)=(sqrt(x+3))/(x-9) ?
The domain of f(x)=(sqrt(x+3))/(x-9) is -3<= x<9\lor x>9