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Popular >

range of f(x)=-x^2+6x-1

Solution

range

f (x) = - x^{2} + 6 x - 1

Solution

f (x) \leq 8

+1

Solution steps

Vertex of

- x^{2} + 6 x - 1 :

Maximum

(3, 8)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (3, 8)

f (x) \leq 8

Popular Examples

extreme f(x)=(x^2+x+2)/(x-1)extreme points

f (x) = \frac{x ^{2} + x + 2}{x - 1}

inverse of f(x)=-x^2-4x-3 inverse

f (x) = - x^{2} - 4 x - 3

domain of f(x)=(12x+48)/(7x-35)domain

f (x) = \frac{12 x + 48}{7 x - 35}

inverse of y= x/(x+2)inverse

y = \frac{x}{x + 2}

distance (0,0),(2,-3)distance

(0, 0), (2, - 3)

Frequently Asked Questions (FAQ)

What is the range of f(x)=-x^2+6x-1 ?
The range of f(x)=-x^2+6x-1 is f(x)<= 8