What is the inverse of 9e^{((w+4)^2)/(32)} ?

The inverse of 9e^{((w+4)^2)/(32)} is 4*2^{1/2}ln^{1/2}(w/9)-4,-4*2^{1/2}ln^{1/2}(w/9)-4

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inverse of 9e^{((w+4)^2)/(32)}

inverse

9 e^{\frac{( w + 4 ) ^{2}}{32}}

4 \cdot 2^{\frac{1}{2}} ln^{\frac{1}{2}} (\frac{w}{9}) - 4, - 4 \cdot 2^{\frac{1}{2}} ln^{\frac{1}{2}} (\frac{w}{9}) - 4

Solution steps

y = 9 e^{\frac{( w + 4 ) ^{2}}{32}}

Replace

w

with

y

w = 9 e^{\frac{( y + 4 ) ^{2}}{32}}

Solve for

y, w = 9 e^{\frac{( y + 4 ) ^{2}}{32}}

4 \cdot 2^{\frac{1}{2}} ln^{\frac{1}{2}} (\frac{w}{9}) - 4, - 4 \cdot 2^{\frac{1}{2}} ln^{\frac{1}{2}} (\frac{w}{9}) - 4

e x t re m e f (x) = 6 x^{4} + 8 x^{3}

in v erse f (x) = x^{5} - 3

d o main f (x) = x + \frac{4}{x}

mi d p o in t (- 2, - 4), (3, - 2)

in f l ec t i o n \frac{1}{2 x}

What is the inverse of 9e^{((w+4)^2)/(32)} ?
The inverse of 9e^{((w+4)^2)/(32)} is 4*2^{1/2}ln^{1/2}(w/9)-4,-4*2^{1/2}ln^{1/2}(w/9)-4