What is the inverse of f(x)=(x-4)/(3x+1) ?

The inverse of f(x)=(x-4)/(3x+1) is (-4-x)/(3x-1)

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inverse of f(x)=(x-4)/(3x+1)

inverse

f (x) = \frac{x - 4}{3 x + 1}

\frac{- 4 - x}{3 x - 1}

Solution steps

y = \frac{x - 4}{3 x + 1}

Replace

x

with

y

x = \frac{y - 4}{3 y + 1}

Solve for

y, x = \frac{y - 4}{3 y + 1}

\frac{- 4 - x}{3 x - 1}

2 + \frac{3}{x}

f (x) = (x + 3)^{2} - 1

arccos (\frac{cos ( x )}{1 + cos ( x )})

- (x + 2) (x - 2) - x + 1

What is the inverse of f(x)=(x-4)/(3x+1) ?
The inverse of f(x)=(x-4)/(3x+1) is (-4-x)/(3x-1)