What is the domain of f(x)= x/(sqrt(16-x^2)) ?

The domain of f(x)= x/(sqrt(16-x^2)) is -4<x<4

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domain of f(x)= x/(sqrt(16-x^2))

domain

f (x) = \frac{x}{16 - x ^{2}}

- 4 < x < 4

Interval Notation

(- 4, 4)

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq 4

Find undefined (singularity) points:

x = 4, x = - 4

Combine real regions and undefined points for final function domain

- 4 < x < 4

sy mm e t ry y = x^{2} - 5 x + 3

d o main f (x) = \frac{x ^{3} - 9 x}{3 x ^{2} - 6 x - 9}

d o main f (x) = \frac{6}{9 - x}

a sy m pt o t es \frac{2}{x - 3}

cr i t i c a l f (x) = 4 x^{3} - 3 x^{2} + 8

What is the domain of f(x)= x/(sqrt(16-x^2)) ?
The domain of f(x)= x/(sqrt(16-x^2)) is -4<x<4