What is the inverse of f(x)=4x^2+3 ?

The inverse of f(x)=4x^2+3 is (sqrt(x-3))/2 ,-(sqrt(x-3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=4x^2+3

inverse

f (x) = 4 x^{2} + 3

\frac{x - 3}{2}, - \frac{x - 3}{2}

Solution steps

y = 4 x^{2} + 3

Replace

x

with

y

x = 4 y^{2} + 3

Solve for

y, x = 4 y^{2} + 3

\frac{x - 3}{2}, - \frac{x - 3}{2}

p er p e n d i c u l a r 5, - 6

d o main f (x) = \frac{3}{x + 5}

s l o p e 8 sin (\frac{π}{6})

d o main g (x) = e^{(e^{x} - 2)}

d o main f (x) = 15 - 3 x

What is the inverse of f(x)=4x^2+3 ?
The inverse of f(x)=4x^2+3 is (sqrt(x-3))/2 ,-(sqrt(x-3))/2