What is the perpendicular y=x+10,(3,-6) ?

The perpendicular y=x+10,(3,-6) is y=-x-3

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perpendicular y=x+10,(3,-6)

perpendicular

y = x + 10, (3, - 6)

y = - x - 3

Solution steps

Find the line

y = mx + b

perpendicular to

y = x + 10

that passes through

(3, - 6)

Find the slope of

y = x + 10 : m = 1

Compute the slope of the perpendicular line:

m_{p} = - 1

Find the line with slope m=

- 1

and passing through

(3, - 6) : y = - x - 3

y = - x - 3

m o n o t o n e x^{2} - 4

in v erse y = x + 6

d o main f (x) = \frac{1}{4 + x}

in v erse f (x) = \frac{5}{6} x + \frac{5}{3}

d o main \frac{2 x}{1 - 5 x}

What is the perpendicular y=x+10,(3,-6) ?
The perpendicular y=x+10,(3,-6) is y=-x-3