What is the domain of f(x)=-3/(sqrt(2-4x)) ?

The domain of f(x)=-3/(sqrt(2-4x)) is x< 1/2

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domain of f(x)=-3/(sqrt(2-4x))

domain

f (x) = - \frac{3}{2 - 4 x}

x < \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2})

Solution steps

Find non-negative values for radicals:

x \leq \frac{1}{2}

Find undefined (singularity) points:

x = \frac{1}{2}

Combine real regions and undefined points for final function domain

x < \frac{1}{2}

d o main f (x) = 4 + x^{2}

in t erce pt s f (x) = 3 x^{4} - 4 x^{3} - 12 x^{2}

l in e m = - 10, (0, 0)

mi d p o in t (- 1, 5), (9, - 1)

a sy m pt o t es f (x) = \frac{( x ^{2} - 2 x )}{x ^{2} - 4}

What is the domain of f(x)=-3/(sqrt(2-4x)) ?
The domain of f(x)=-3/(sqrt(2-4x)) is x< 1/2