What is the perpendicular y= 3/2 x-4,(4,-2) ?

The perpendicular y= 3/2 x-4,(4,-2) is y=-2/3 x+2/3

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perpendicular y= 3/2 x-4,(4,-2)

perpendicular

y = \frac{3}{2} x - 4, (4, - 2)

y = - \frac{2}{3} x + \frac{2}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{3}{2} x - 4

that passes through

(4, - 2)

Find the slope of

y = \frac{3}{2} x - 4 : m = \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = - \frac{2}{3}

Find the line with slope m=

- \frac{2}{3}

and passing through

(4, - 2) : y = - \frac{2}{3} x + \frac{2}{3}

y = - \frac{2}{3} x + \frac{2}{3}

x = - 5 (1.4)

\frac{1}{( x + 2 ) ( x - 3 )}

y = 2 x^{2}

f (x) = x^{2} + 2

lo g_{4} (- 2 x + 8)

What is the perpendicular y= 3/2 x-4,(4,-2) ?
The perpendicular y= 3/2 x-4,(4,-2) is y=-2/3 x+2/3