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midpoint
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f(x)=x^2+xextreme f(x)=(x-4)^2symmetry x^2+y^2+6x-2y-15=0domain of f(x)=sqrt(12+3x)simplify (12.3)(-9.1)
Frequently Asked Questions (FAQ)
What is the midpoint (-1,4),(4,-2) ?
The midpoint (-1,4),(4,-2) is (3/2 ,1)