What is the domain of f(x)=((x/(x+3)))/((x/(x+3))+3) ?

The domain of f(x)=((x/(x+3)))/((x/(x+3))+3) is x -9/4

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domain of f(x)=((x/(x+3)))/((x/(x+3))+3)

domain

f (x) = \frac{( \frac{x}{x + 3} )}{( \frac{x}{x + 3} ) + 3}

x < - 3 or - 3 < x < - \frac{9}{4} or x > - \frac{9}{4}

Interval Notation

(- \infty, - 3) \cup (- 3, - \frac{9}{4}) \cup (- \frac{9}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{9}{4}, x = - 3

The function domain

x < - 3 or - 3 < x < - \frac{9}{4} or x > - \frac{9}{4}

r an g e - (2)^{x} + 3

in v erse f (x) = \frac{( x - 2 )}{x + 3}

in v erse f (x) = 2^{x + 4}

d o main f (x) = x^{2} + 5 x - 14

in v erse f (x) = x^{2} - 5, x \leq 0

What is the domain of f(x)=((x/(x+3)))/((x/(x+3))+3) ?
The domain of f(x)=((x/(x+3)))/((x/(x+3))+3) is x<-3\lor-3<x<-9/4 \lor x>-9/4