What is the domain of f(x)=(sqrt(1+x))/(6-x) ?

The domain of f(x)=(sqrt(1+x))/(6-x) is -1 6

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domain of f(x)=(sqrt(1+x))/(6-x)

domain

f (x) = \frac{1 + x}{6 - x}

- 1 \leq x < 6 or x > 6

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 6

Combine real regions and undefined points for final function domain

- 1 \leq x < 6 or x > 6

f (x) = arcsin (\frac{x}{2})

(\frac{1}{3})^{x}

f (x) = - x^{4} + 8 x^{2} - 8

f (x) = \frac{2}{\frac{x}{x + 2}}

\frac{5 x}{x ^{2} - 9}

What is the domain of f(x)=(sqrt(1+x))/(6-x) ?
The domain of f(x)=(sqrt(1+x))/(6-x) is -1<= x<6\lor x>6