What is the asymptotes of f(x)=(6x^3-x^9)/(2x^2-3x) ?

The asymptotes of f(x)=(6x^3-x^9)/(2x^2-3x) is Vertical: x= 3/2

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asymptotes of f(x)=(6x^3-x^9)/(2x^2-3x)

asymptotes

f (x) = \frac{6 x ^{3} - x ^{9}}{2 x ^{2} - 3 x}

Vertical : x = \frac{3}{2}

Solution steps

Vertical asymptotes of

\frac{6 x ^{3} - x ^{9}}{2 x ^{2} - 3 x} : x = \frac{3}{2}

Horizontal Asymptotes of

\frac{6 x ^{3} - x ^{9}}{2 x ^{2} - 3 x} :

None

Slant Asymptotes of

\frac{6 x ^{3} - x ^{9}}{2 x ^{2} - 3 x} :

None

Vertical : x = \frac{3}{2}

p a r a ll e l 5 x - 4 y = 12

e x t re m e f (x) = - x^{3} + 192 ln (x)

e x t re m e f (x) = x^{3} - 12 x + 6

d o main f (x) = \frac{1}{x} + 2

in v erse f (x) = x + \frac{2}{3}

What is the asymptotes of f(x)=(6x^3-x^9)/(2x^2-3x) ?
The asymptotes of f(x)=(6x^3-x^9)/(2x^2-3x) is Vertical: x= 3/2