What is the domain of \sqrt[4]{(w-3)(w+2)(w+4)} ?

The domain of \sqrt[4]{(w-3)(w+2)(w+4)} is -4 = 3

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domain of \sqrt[4]{(w-3)(w+2)(w+4)}

domain

- 4 \leq w \leq - 2 or w \geq 3

Interval Notation

[- 4, - 2] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

- 4 \leq w \leq - 2 or w \geq 3

The function domain

- 4 \leq w \leq - 2 or w \geq 3

g (x) = 4 - x

- 6 x + 2 y = 5, (- 24, - 2)

(- 4, 5), (7, - 9)

X^{2} + 1

(0, 10), (5, - 1)

What is the domain of \sqrt[4]{(w-3)(w+2)(w+4)} ?
The domain of \sqrt[4]{(w-3)(w+2)(w+4)} is -4<= w<=-2\lor w>= 3