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Popular >

distance (-2,5),(4,1)

Solution

distance

(- 2, 5), (4, 1)

Solution

213

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, 5)

and

(4, 1)

is

= (4 - (- 2))^{2} + (1 - 5)^{2}

Simplify

= 213

Popular Examples

domain of f(x)=(4x)/(7-x)domain

f (x) = \frac{4 x}{7 - x}

parity f(x)=x^5+3x^3-x parity

f (x) = x^{5} + 3 x^{3} - x

domain of f(x)=3sqrt(x+2)+3 domain

f (x) = 3 x + 2 + 3

parity f(x)= x/(x^2+2)parity

f (x) = \frac{x}{x ^{2} + 2}

intercepts of f(x)=x^2-xy+y=1 intercepts

f (x) = x^{2} - x y + y = 1

Frequently Asked Questions (FAQ)

What is the distance (-2,5),(4,1) ?
The distance (-2,5),(4,1) is 2sqrt(13)