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Popular >

distance (2,5),(6,-4)

Solution

distance

(2, 5), (6, - 4)

Solution

97

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, 5)

and

(6, - 4)

is

= (6 - 2)^{2} + (- 4 - 5)^{2}

Simplify

= 97

Popular Examples

asymptotes of-ln(x^2-1)asymptotes

- ln (x^{2} - 1)

intercepts of f(x)=4x^2-24x+34 intercepts

f (x) = 4 x^{2} - 24 x + 34

domain of (x/(x+7))/(x/(x+7)+7)domain

\frac{\frac{x}{x + 7}}{\frac{x}{x + 7} + 7}

critical f(x)=6x^{2/3}+x^{5/3}critical points

f (x) = 6 x^{\frac{2}{3}} + x^{\frac{5}{3}}

range of f(x)=sqrt(3x-4)range

f (x) = 3 x - 4

Frequently Asked Questions (FAQ)

What is the distance (2,5),(6,-4) ?
The distance (2,5),(6,-4) is square root of 97