What is the domain of f(x)=sqrt(1-9x) ?

The domain of f(x)=sqrt(1-9x) is x<= 1/9

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domain of f(x)=sqrt(1-9x)

domain

f (x) = 1 - 9 x

x \leq \frac{1}{9}

Interval Notation

(- \infty, \frac{1}{9}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{1}{9}

The function domain

x \leq \frac{1}{9}

d o main f (x) = \frac{1}{( x - 8 ) ^{2}} + 9

in v erse f (x) = 6 x + 6

in v erse f (x) = 3 x + 2 + 2

in v erse f (x) = \frac{( x - 5 )}{4}

a sy m pt o t es f (x) = \frac{x ^{2} + 3}{5 x - 2 x ^{2}}

What is the domain of f(x)=sqrt(1-9x) ?
The domain of f(x)=sqrt(1-9x) is x<= 1/9