What is the inverse of f(x)=1-log_{5}(x-2) ?

The inverse of f(x)=1-log_{5}(x-2) is 5^{1-x}+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=1-log_{5}(x-2)

inverse

f (x) = 1 - lo g_{5} (x - 2)

5^{1 - x} + 2

Solution steps

y = 1 - lo g_{5} (x - 2)

Replace

x

with

y

x = 1 - lo g_{5} (y - 2)

Solve for

y, x = 1 - lo g_{5} (y - 2)

5^{1 - x} + 2

p er i o d i c i t y f (x) = 2 cos (\frac{2 π x}{3} + \frac{3}{5})

in v erse f (x) = 16 - x^{2}

a sy m pt o t es f (x) = \frac{x + 1}{x ^{2} - 3 x - 4}

in v erse f (x) = lo g_{4} (16 x)

d o main (\frac{1}{x})^{2} - 4 (\frac{1}{x})

What is the inverse of f(x)=1-log_{5}(x-2) ?
The inverse of f(x)=1-log_{5}(x-2) is 5^{1-x}+2