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Popular >

range of f(x)=x^2+2x

Solution

range

f (x) = x^{2} + 2 x

Solution

f (x) \geq - 1

+1

Interval Notation

Solution steps

Vertex of

x^{2} + 2 x :

Minimum

(- 1, - 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 1, - 1)

f (x) \geq - 1

Graph

Popular Examples

domain of f(x)= 1/(sqrt(16-x^2))domain

f (x) = \frac{1}{16 - x ^{2}}

asymptotes of f(x)= 6/((x-5)^3)asymptotes

f (x) = \frac{6}{( x - 5 ) ^{3}}

inverse of f(x)=(x+6)/(x-7)inverse

f (x) = \frac{x + 6}{x - 7}

range of f(x)=(x+1)/(x^2-4)range

f (x) = \frac{x + 1}{x ^{2} - 4}

range of f(x)=x^2-x-2 range

f (x) = x^{2} - x - 2

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2+2x ?
The range of f(x)=x^2+2x is f(x)>=-1