What is the perpendicular y=2x-3,(-7,-2) ?

The perpendicular y=2x-3,(-7,-2) is y=-1/2 x-11/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular y=2x-3,(-7,-2)

perpendicular

y = 2 x - 3, (- 7, - 2)

y = - \frac{1}{2} x - \frac{11}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 2 x - 3

that passes through

(- 7, - 2)

Find the slope of

y = 2 x - 3 : m = 2

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(- 7, - 2) : y = - \frac{1}{2} x - \frac{11}{2}

y = - \frac{1}{2} x - \frac{11}{2}

(- 4, - 1), (- 1, 4)

3 x^{2} + 4

3 x - 2 (x + 1) = 2 y - 4 x

f (x) = 5 sin (x) + 5 cos (x)

f (x) = \frac{x - 2}{x - 5}

What is the perpendicular y=2x-3,(-7,-2) ?
The perpendicular y=2x-3,(-7,-2) is y=-1/2 x-11/2