What is the domain of f(x)=sqrt(x-1) ?

The domain of f(x)=sqrt(x-1) is x>= 1

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domain of f(x)=sqrt(x-1)

domain

f (x) = x - 1

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

d o main f (x) = \frac{5 + x}{x ^{2} - 49}

cr i t i c a l e^{l n (x) + 1} - 5 cos (3 x)

d o main f (x) = \frac{ln ( x )}{ln ( 3 )}

d o main \frac{2 x}{x - 5}

e x t re m e f (x) = 6 x^{2} - 6 x