What is the domain of f(x)=(x+3)/(x^2+4x+3) ?

The domain of f(x)=(x+3)/(x^2+4x+3) is x -1

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domain of f(x)=(x+3)/(x^2+4x+3)

domain

f (x) = \frac{x + 3}{x ^{2} + 4 x + 3}

x < - 3 or - 3 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 3

The function domain

x < - 3 or - 3 < x < - 1 or x > - 1

s l o p e y = - \frac{4}{12} x + b

in v erse f (x) = \frac{3 x + 5}{x}

p a r i t y x cot (x^{2})

a sy m pt o t es \frac{6 x + 7}{3 x + 2}

r an g e 3 - 2 x - 1

What is the domain of f(x)=(x+3)/(x^2+4x+3) ?
The domain of f(x)=(x+3)/(x^2+4x+3) is x<-3\lor-3<x<-1\lor x>-1