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Popular Functions >

range of f(x)=x^2+6x+8

Solution

range

f (x) = x^{2} + 6 x + 8

Solution

f (x) \geq - 1

+1

Interval Notation

[- 1, \infty)

Solution steps

Vertex of

x^{2} + 6 x + 8 :

Minimum

(- 3, - 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 3, - 1)

f (x) \geq - 1

Graph

Popular Examples

domain of f(x)=12x+3

d o main f (x) = 12 x + 3

domain of f(x)=\sqrt[4]{ln(x)}

d o main f (x) = 4 ln (x)

domain of f(x)=sqrt(9x+3)

d o main f (x) = 9 x + 3

critical f(x)=x^2e^{4x}

cr i t i c a l f (x) = x^{2} e^{4 x}

perpendicular 2x+6y=1,(-2,2)

p er p e n d i c u l a r 2 x + 6 y = 1, (- 2, 2)

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2+6x+8 ?
The range of f(x)=x^2+6x+8 is f(x)>=-1