What is the critical x^4-2x^2+1 ?

The critical x^4-2x^2+1 is x=-1,x=0,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical x^4-2x^2+1

critical points

x^{4} - 2 x^{2} + 1

x = - 1, x = 0, x = 1

Solution steps

x^{4} - 2 x^{2} + 1

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 0, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 2 x^{2} + 1 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 0, x = 1

f (x) = \frac{3}{x - 4}

\frac{x - 3}{2}

f (x) = \frac{1}{2} lo g_{2} (x - 3) + 2

(x + 2)^{2}

\frac{x - 4}{x + 2}