What is the perpendicular 6x+4y=3 ?

The perpendicular 6x+4y=3 is y= 2/3 x+b

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perpendicular 6x+4y=3

perpendicular

6 x + 4 y = 3

y = \frac{2}{3} x + b

Solution steps

Find the slope of

6 x + 4 y = 3 : m = - \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = \frac{2}{3}

Line with slope m=

\frac{2}{3} : y = \frac{2}{3} x + b

y = \frac{2}{3} x + b

m o n o t o n e f (x) = 2 x^{3} + 24 x^{2} + 72 x

p a r i t y f (x) = x - 4

in v erse f (x) = \frac{2 x}{7} - 14

l in e (- 2, 1), (0, 5)

y = x^{2} - 7 x + 12