What is the inverse of y=3x^2+x+2 ?

The inverse of y=3x^2+x+2 is (-1+sqrt(12x-23))/6 ,(-1-sqrt(12x-23))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of y=3x^2+x+2

inverse

y = 3 x^{2} + x + 2

\frac{- 1 + 12 x - 23}{6}, \frac{- 1 - 12 x - 23}{6}

Solution steps

y = 3 x^{2} + x + 2

Replace

x

with

y

x = 3 y^{2} + y + 2

Solve for

y, x = 3 y^{2} + y + 2

\frac{- 1 + 12 x - 23}{6}, \frac{- 1 - 12 x - 23}{6}

in f l ec t i o n f (x) = - 2 x e^{- 3 x}

r an g e f (x) = 3 x^{2} - 6

p er p e n d i c u l a r 3 x + 6 y = 5, at

l in e (2, 3), (1, 0)

a sy m pt o t es f (x) = \frac{x ^{2} - 1}{x + 2}

What is the inverse of y=3x^2+x+2 ?
The inverse of y=3x^2+x+2 is (-1+sqrt(12x-23))/6 ,(-1-sqrt(12x-23))/6